# Write an equation of the line that passes through the given point and is parallel to the given line

• The equation for a line is of the form y=mx+b, where m represents the slope and b represents the intersection of the line with the the y-axis. This article will show by an example how we can write an equation for the line that has a given slope and passes through a given point.
Question 217384: write an equation of the line that passes through the given point and is parallel to the given line. write the answer in slope-intercept form. (0,8), 4y - 8x = 9 Answer by checkley77(12844) (Show Source):

Example 2 Determine if the line that passes through the point (0,−3,8) (0, − 3, 8) and is parallel to the line given by x = 10+3t x = 10 + 3 t, y = 12t y = 12 t and z =−3−t z = − 3 − t passes through the xz x z -plane. If it does give the coordinates of that point.

line that passes through the point (2, 3) with a slope of º1 2. Notice that the line has a y-intercept of 4, which agrees with the slope-intercept form found above. Writing Equations of Perpendicular and Parallel Lines Write an equation of the line that passes through (3, 2) and is (a) perpendicular and (b) parallel to the line y = º3x + 2 ...
• Given line A and point P, Sal finds the equation of the line perpendicular to A that passes through P. If you're seeing this message, it means we're having trouble loading external resources on our website.
• Find the Equation of a Line Given That You Know a Point on the Line And Its Slope The equation of a line is typically written as y=mx+b where m is the slope and b is the y-intercept. If you a point that a line passes through, and its slope, this page will show you how to find the equation of the line.
• The equation of a pencil of straight lines passing through a given point A (x 1, y 1) y-y 1 = k (x-x 1). (2) 3°. The equation of a straight line passing through two given points A (xu y 1) and B (x 2, y 2) (3) 4°. The point of intersection of two non-parallel straight lines A 1 x+ B 1 y+C 1 =0 and A 2 x+ BaY+C 2 = 0 is found by solving the ...

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Question 792381: Write the equation of a line parallel to the given line but passing through the given point. y=-1/2x+1 (4,2) Then write the equation of a line perpendicular to the given line but passing through the given point. Y=-3x-6; (-1,5) *I believe I have the second part complete.

Mar 29, 2013 · What you need is a vector V2, such that it is perpendicular to V1 and the equation of the line going through point P2 (1,0,5) parallel to V2, also intersect L1 in P3 (xo,yo,zo). V2 could be [ xo-1,...

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The equation of a line in standard form is y = mx + b where m=slope. For this ONE poinnt the equation looks like -5 = m (-4) -1 or y = x -1 for a slope of 2 it looks like -5 = (2) (-4) + 3 or y = mx - (5+mx) 3 -5 = (3) (-4) + 7 4 -5= (4) (-4) + 11

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The equation of a line in standard form is y = mx + b where m=slope. For this ONE poinnt the equation looks like -5 = m (-4) -1 or y = x -1 for a slope of 2 it looks like -5 = (2) (-4) + 3 or y = mx - (5+mx) 3 -5 = (3) (-4) + 7 4 -5= (4) (-4) + 11

Write the equation of a line that is perpendicular to the given line and that passes through the given point. Answers · 1 Tell whether the lines for the pair of equations are parallel, perpendicular, or neither.

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Write the equation of a line that is perpendicular to the given line and that passes through the given point. Answers · 1 Tell whether the lines for the pair of equations are parallel, perpendicular, or neither.

Write the equation of a line parallel to the given line but passing through the given point. y=-1/2x+1 (4,2)

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Given line A and point P, Sal finds the equation of the line perpendicular to A that passes through P. If you're seeing this message, it means we're having trouble loading external resources on our website.

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, parallel to the plane π but not parallel between them, are called direction vectors of the plane π. Let The vector P0P from a specific point P0(x0,y0,z0) to a generic point P(x,y,z)of the plane is a linear combination of direction vectors u r and v r: P0P =su +tv; s,t∈R r r The vector equation of the plane is: :r =r0 +su +tv; s,t∈R r r r r π Ex 1.

The equation of a line in standard form is y = mx + b where m=slope. For this ONE poinnt the equation looks like -5 = m (-4) -1 or y = x -1 for a slope of 2 it looks like -5 = (2) (-4) + 3 or y = mx - (5+mx) 3 -5 = (3) (-4) + 7 4 -5= (4) (-4) + 11

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4. The equation of a straight line with given gradient, passing through a given point Example Suppose that we want to ﬁnd the equation of a line which has a gradient of 1 3 and passes through the point (1,2). Here, whilst we know the gradient, we do not know the value of the y-intercept c. We start with the general equation of a straight line ...

Write the equation of a straight line passing through the point M of intersection of the straight lines 2x-3y+ +5 = 0 and 3x + y-7 = 0 perpendicular to the straight line y = 2x (without finding the point M). 1.7. Miscellaneous Problems.121. Through the origin draw a straight line forming with the straight lines x + y "'""a and x = 0 a triangle ...

Finding the Equation of a Line Given a Point and a Slope. Finding the Equation of a Line Given Two Points. Parallel Lines.
Find sets of (a) parametric equations and (b) Symmetric equations of the line through the point parallel to the given vector or line (if possible). (For each line, write the direction numbers as integers.) Point parallel to (- 2, 0, 3) V = 2i + 4j - 2k
Step 1. Substitute the slope from original line (3 in this case) into the equation of the line. y = 3 x + b. Step 2. Substitute the given point (1, 7) into the x and y values. y = 3 x + b 7 = 3 ( 1) + b. Step 3. Solve for b (the y-intercept ) 7 = 3 ( 1) + b 7 = 3 + b − 3 − 3 4 = b.
This Algebra Cruncher generates an endless number of practice problems for finding the equation of the line that is parallel to a given line and that passes through a given point -- with hints and solutions!